Étiquette : Maths
1–1+1–1+1–1 ⋯ = 1/2
A = 1–1+1–1+1–1⋯
1-A=1-(1–1+1–1+1–1⋯)
1-A=1–1+1–1+1–1+1⋯
1-A =A
1-A+A=A+A
1 = 2A
1/2 = A
Part of the Ramanujan Summation.
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A = 1–1+1–1+1–1⋯
1-A=1-(1–1+1–1+1–1⋯)
1-A=1–1+1–1+1–1+1⋯
1-A =A
1-A+A=A+A
1 = 2A
1/2 = A
Part of the Ramanujan Summation.